Base | Representation |
---|---|
bin | 10100111111100001… |
… | …001010000100101101 |
3 | 2011011212220200121211 |
4 | 110333201022010231 |
5 | 332130331234401 |
6 | 14204400554421 |
7 | 1425401013220 |
oct | 247741120455 |
9 | 64155820554 |
10 | 22540493101 |
11 | 96175800a5 |
12 | 4450922a11 |
13 | 2182b141a9 |
14 | 113b8775b7 |
15 | 8bdce4951 |
hex | 53f84a12d |
22540493101 has 4 divisors (see below), whose sum is σ = 25760563552. Its totient is φ = 19320422652.
The previous prime is 22540493093. The next prime is 22540493147. The reversal of 22540493101 is 10139404522.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22540493101 - 23 = 22540493093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (22540493161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1610035215 + ... + 1610035228.
It is an arithmetic number, because the mean of its divisors is an integer number (6440140888).
Almost surely, 222540493101 is an apocalyptic number.
It is an amenable number.
22540493101 is a deficient number, since it is larger than the sum of its proper divisors (3220070451).
22540493101 is an equidigital number, since it uses as much as digits as its factorization.
22540493101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3220070450.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 22540493101 its reverse (10139404522), we get a palindrome (32679897623).
The spelling of 22540493101 in words is "twenty-two billion, five hundred forty million, four hundred ninety-three thousand, one hundred one".
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