Base | Representation |
---|---|
bin | 1010011101011001011110… |
… | …10010011001111100110010 |
3 | 10000102210220110120101002002 |
4 | 11032230233102121330302 |
5 | 11003314200331132424 |
6 | 120530113430054002 |
7 | 4562501642442254 |
oct | 516545722317462 |
9 | 100383813511062 |
10 | 23000343224114 |
11 | 7368433150103 |
12 | 26b57544aa302 |
13 | caabccc66919 |
14 | 597318979cd4 |
15 | 29d4597c5cae |
hex | 14eb2f499f32 |
23000343224114 has 4 divisors (see below), whose sum is σ = 34500514836174. Its totient is φ = 11500171612056.
The previous prime is 23000343224099. The next prime is 23000343224149. The reversal of 23000343224114 is 41142234300032.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 22479138641089 + 521204583025 = 4741217^2 + 721945^2 .
It is a super-3 number, since 3×230003432241143 (a number of 41 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750085806027 + ... + 5750085806030.
Almost surely, 223000343224114 is an apocalyptic number.
23000343224114 is a deficient number, since it is larger than the sum of its proper divisors (11500171612060).
23000343224114 is a wasteful number, since it uses less digits than its factorization.
23000343224114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11500171612059.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 23000343224114 its reverse (41142234300032), we get a palindrome (64142577524146).
The spelling of 23000343224114 in words is "twenty-three trillion, three hundred forty-three million, two hundred twenty-four thousand, one hundred fourteen".
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