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23000343224114 = 211500171612057
BaseRepresentation
bin1010011101011001011110…
…10010011001111100110010
310000102210220110120101002002
411032230233102121330302
511003314200331132424
6120530113430054002
74562501642442254
oct516545722317462
9100383813511062
1023000343224114
117368433150103
1226b57544aa302
13caabccc66919
14597318979cd4
1529d4597c5cae
hex14eb2f499f32

23000343224114 has 4 divisors (see below), whose sum is σ = 34500514836174. Its totient is φ = 11500171612056.

The previous prime is 23000343224099. The next prime is 23000343224149. The reversal of 23000343224114 is 41142234300032.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 22479138641089 + 521204583025 = 4741217^2 + 721945^2 .

It is a super-3 number, since 3×230003432241143 (a number of 41 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750085806027 + ... + 5750085806030.

Almost surely, 223000343224114 is an apocalyptic number.

23000343224114 is a deficient number, since it is larger than the sum of its proper divisors (11500171612060).

23000343224114 is a wasteful number, since it uses less digits than its factorization.

23000343224114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11500171612059.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 23000343224114 its reverse (41142234300032), we get a palindrome (64142577524146).

The spelling of 23000343224114 in words is "twenty-three trillion, three hundred forty-three million, two hundred twenty-four thousand, one hundred fourteen".

Divisors: 1 2 11500171612057 23000343224114