Base | Representation |
---|---|
bin | 1010011101011011011101… |
… | …11000010101010010100111 |
3 | 10000102220122211010212100001 |
4 | 11032231232320111102213 |
5 | 11003323341443143421 |
6 | 120530411341402131 |
7 | 4562540246135266 |
oct | 516555670252247 |
9 | 100386584125301 |
10 | 23001410131111 |
11 | 7368930412125 |
12 | 26b59b1869347 |
13 | cab03cccb839 |
14 | 5973ba5425dd |
15 | 29d4bd2c1691 |
hex | 14eb6ee154a7 |
23001410131111 has 4 divisors (see below), whose sum is σ = 23536326645832. Its totient is φ = 22466493616392.
The previous prime is 23001410131097. The next prime is 23001410131151. The reversal of 23001410131111 is 11113101410032.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23001410131111 - 27 = 23001410130983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23001410131151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 267458257296 + ... + 267458257381.
It is an arithmetic number, because the mean of its divisors is an integer number (5884081661458).
Almost surely, 223001410131111 is an apocalyptic number.
23001410131111 is a deficient number, since it is larger than the sum of its proper divisors (534916514721).
23001410131111 is an equidigital number, since it uses as much as digits as its factorization.
23001410131111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 534916514720.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 23001410131111 its reverse (11113101410032), we get a palindrome (34114511541143).
The spelling of 23001410131111 in words is "twenty-three trillion, one billion, four hundred ten million, one hundred thirty-one thousand, one hundred eleven".
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