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230100121133 = 1495115390283
BaseRepresentation
bin1101011001001100001…
…0010011011000101101
3210222221001222021020122
43112103002103120231
512232221112334013
6253412340054325
722424044521131
oct3262302233055
9728831867218
10230100121133
1189648579773
12387180943a5
131891036ac3c
14b1cb94d3c1
155ebac78a08
hex359309362d

230100121133 has 4 divisors (see below), whose sum is σ = 230115526368. Its totient is φ = 230084715900.

The previous prime is 230100121061. The next prime is 230100121217. The reversal of 230100121133 is 331121001032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 230100121133 - 210 = 230100120109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (230100121633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7680191 + ... + 7710092.

It is an arithmetic number, because the mean of its divisors is an integer number (57528881592).

Almost surely, 2230100121133 is an apocalyptic number.

It is an amenable number.

230100121133 is a deficient number, since it is larger than the sum of its proper divisors (15405235).

230100121133 is a wasteful number, since it uses less digits than its factorization.

230100121133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15405234.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 230100121133 its reverse (331121001032), we get a palindrome (561221122165).

The spelling of 230100121133 in words is "two hundred thirty billion, one hundred million, one hundred twenty-one thousand, one hundred thirty-three".

Divisors: 1 14951 15390283 230100121133