Base | Representation |
---|---|
bin | 10101011100001110… |
… | …000011011011110001 |
3 | 2012102110000000102121 |
4 | 111130032003123301 |
5 | 334122114240213 |
6 | 14324241514241 |
7 | 1443335656522 |
oct | 253416033361 |
9 | 65373000377 |
10 | 23022024433 |
11 | 9844372781 |
12 | 4566042981 |
13 | 222b800b85 |
14 | 11857c2849 |
15 | 8eb21088d |
hex | 55c3836f1 |
23022024433 has 4 divisors (see below), whose sum is σ = 23029704000. Its totient is φ = 23014344868.
The previous prime is 23022024413. The next prime is 23022024437. The reversal of 23022024433 is 33442022032.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23022024433 - 25 = 23022024401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23022024398 and 23022024407.
It is not an unprimeable number, because it can be changed into a prime (23022024437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3835285 + ... + 3841282.
It is an arithmetic number, because the mean of its divisors is an integer number (5757426000).
Almost surely, 223022024433 is an apocalyptic number.
It is an amenable number.
23022024433 is a deficient number, since it is larger than the sum of its proper divisors (7679567).
23022024433 is an equidigital number, since it uses as much as digits as its factorization.
23022024433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7679566.
The product of its (nonzero) digits is 6912, while the sum is 25.
Adding to 23022024433 its reverse (33442022032), we get a palindrome (56464046465).
The spelling of 23022024433 in words is "twenty-three billion, twenty-two million, twenty-four thousand, four hundred thirty-three".
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