Base | Representation |
---|---|
bin | 1010011110010011001010… |
… | …01111010011100101001111 |
3 | 10000112202211210221201211122 |
4 | 11033021211033103211033 |
5 | 11004321112131333320 |
6 | 120552234511111155 |
7 | 4564646260464215 |
oct | 517114517234517 |
9 | 100482753851748 |
10 | 23031313152335 |
11 | 737a585938604 |
12 | 26bb7582124bb |
13 | cb0ac726a337 |
14 | 598a15b44cb5 |
15 | 29e16d640d25 |
hex | 14f2653d394f |
23031313152335 has 4 divisors (see below), whose sum is σ = 27637575782808. Its totient is φ = 18425050521864.
The previous prime is 23031313152299. The next prime is 23031313152343. The reversal of 23031313152335 is 53325131313032.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23031313152335 - 234 = 23014133283151 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23031313152295 and 23031313152304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2303131315229 + ... + 2303131315238.
It is an arithmetic number, because the mean of its divisors is an integer number (6909393945702).
Almost surely, 223031313152335 is an apocalyptic number.
23031313152335 is a deficient number, since it is larger than the sum of its proper divisors (4606262630473).
23031313152335 is an equidigital number, since it uses as much as digits as its factorization.
23031313152335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4606262630472.
The product of its (nonzero) digits is 72900, while the sum is 35.
Adding to 23031313152335 its reverse (53325131313032), we get a palindrome (76356444465367).
The spelling of 23031313152335 in words is "twenty-three trillion, thirty-one billion, three hundred thirteen million, one hundred fifty-two thousand, three hundred thirty-five".
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