Base | Representation |
---|---|
bin | 1010011110100110000010… |
… | …00010110011100111000001 |
3 | 10000120201222210122021100121 |
4 | 11033103001002303213001 |
5 | 11010002333442022423 |
6 | 121001032023420241 |
7 | 4565455305442450 |
oct | 517230102634701 |
9 | 100521883567317 |
10 | 23041443314113 |
11 | 7383904075034 |
12 | 27017048b4681 |
13 | cb1a4cbcbac3 |
14 | 5992d72aab97 |
15 | 29e562b6045d |
hex | 14f4c10b39c1 |
23041443314113 has 16 divisors (see below), whose sum is σ = 26598238392960. Its totient is φ = 19551361003776.
The previous prime is 23041443314089. The next prime is 23041443314137. The reversal of 23041443314113 is 31141334414032.
It is an interprime number because it is at equal distance from previous prime (23041443314089) and next prime (23041443314137).
It is not a de Polignac number, because 23041443314113 - 25 = 23041443314081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23041443614113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16957398 + ... + 18265711.
It is an arithmetic number, because the mean of its divisors is an integer number (1662389899560).
Almost surely, 223041443314113 is an apocalyptic number.
It is an amenable number.
23041443314113 is a deficient number, since it is larger than the sum of its proper divisors (3556795078847).
23041443314113 is a wasteful number, since it uses less digits than its factorization.
23041443314113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35224056.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 23041443314113 its reverse (31141334414032), we get a palindrome (54182777728145).
The spelling of 23041443314113 in words is "twenty-three trillion, forty-one billion, four hundred forty-three million, three hundred fourteen thousand, one hundred thirteen".
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