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23042013 = 37680671
BaseRepresentation
bin101011111100…
…1011111011101
31121100122200220
41113321133131
521344321023
62141511553
7366565611
oct127713735
947318626
1023042013
1112008895
1278725b9
134a09c37
1430bb341
1520523e3
hex15f97dd

23042013 has 4 divisors (see below), whose sum is σ = 30722688. Its totient is φ = 15361340.

The previous prime is 23041999. The next prime is 23042017. The reversal of 23042013 is 31024032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23042013 - 25 = 23041981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23041983 and 23042001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23042017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3840333 + ... + 3840338.

It is an arithmetic number, because the mean of its divisors is an integer number (7680672).

Almost surely, 223042013 is an apocalyptic number.

It is an amenable number.

23042013 is a deficient number, since it is larger than the sum of its proper divisors (7680675).

23042013 is an equidigital number, since it uses as much as digits as its factorization.

23042013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7680674.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 23042013 is about 4800.2096829201. The cubic root of 23042013 is about 284.5597511853.

Adding to 23042013 its reverse (31024032), we get a palindrome (54066045).

The spelling of 23042013 in words is "twenty-three million, forty-two thousand, thirteen".

Divisors: 1 3 7680671 23042013