Search a number
-
+
23044100133 = 37681366711
BaseRepresentation
bin10101011101100010…
…010001000000100101
32012110222112120121010
4111131202101000211
5334143242201013
614330351012433
71444024422255
oct253542210045
965428476533
1023044100133
11985588055a
12457150a119
132233260012
1411886cb965
158ed1217c3
hex55d891025

23044100133 has 4 divisors (see below), whose sum is σ = 30725466848. Its totient is φ = 15362733420.

The previous prime is 23044100119. The next prime is 23044100137. The reversal of 23044100133 is 33100144032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 23044100133 - 29 = 23044099621 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23044100137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3840683353 + ... + 3840683358.

It is an arithmetic number, because the mean of its divisors is an integer number (7681366712).

Almost surely, 223044100133 is an apocalyptic number.

It is an amenable number.

23044100133 is a deficient number, since it is larger than the sum of its proper divisors (7681366715).

23044100133 is an equidigital number, since it uses as much as digits as its factorization.

23044100133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7681366714.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 23044100133 its reverse (33100144032), we get a palindrome (56144244165).

The spelling of 23044100133 in words is "twenty-three billion, forty-four million, one hundred thousand, one hundred thirty-three".

Divisors: 1 3 7681366711 23044100133