Base | Representation |
---|---|
bin | 100001100011001011001… |
… | …000001110111111001101 |
3 | 22011101220222120101222220 |
4 | 201203023020032333031 |
5 | 300233141130412140 |
6 | 4523045321125553 |
7 | 325365461043342 |
oct | 41431310167715 |
9 | 8141828511886 |
10 | 2305510404045 |
11 | 809841578212 |
12 | 3129a69298b9 |
13 | 139540baa394 |
14 | 7d8317967c9 |
15 | 3ee89313bd0 |
hex | 218cb20efcd |
2305510404045 has 16 divisors (see below), whose sum is σ = 3689806490880. Its totient is φ = 1229275600704.
The previous prime is 2305510404013. The next prime is 2305510404061. The reversal of 2305510404045 is 5404040155032.
2305510404045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2305510404045 - 25 = 2305510404013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2305510403997 and 2305510404015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20563990 + ... + 20675799.
It is an arithmetic number, because the mean of its divisors is an integer number (230612905680).
Almost surely, 22305510404045 is an apocalyptic number.
It is an amenable number.
2305510404045 is a deficient number, since it is larger than the sum of its proper divisors (1384296086835).
2305510404045 is a wasteful number, since it uses less digits than its factorization.
2305510404045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41243524.
The product of its (nonzero) digits is 48000, while the sum is 33.
Adding to 2305510404045 its reverse (5404040155032), we get a palindrome (7709550559077).
The spelling of 2305510404045 in words is "two trillion, three hundred five billion, five hundred ten million, four hundred four thousand, forty-five".
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