Base | Representation |
---|---|
bin | 1010100000010011010011… |
… | …00001001011001011110011 |
3 | 10000210100101222212022120220 |
4 | 11100021221201023023303 |
5 | 11011433003213002011 |
6 | 121044012542504123 |
7 | 4602633056565132 |
oct | 520115141131363 |
9 | 100710358768526 |
10 | 23100104422131 |
11 | 73a67768007a0 |
12 | 2710b56295043 |
13 | cb743b1548c9 |
14 | 59c09ddd7919 |
15 | 2a0d47a8e506 |
hex | 15026984b2f3 |
23100104422131 has 8 divisors (see below), whose sum is σ = 33600151886784. Its totient is φ = 14000063286120.
The previous prime is 23100104422081. The next prime is 23100104422133. The reversal of 23100104422131 is 13122440100132.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 23100104422131 - 217 = 23100104291059 is a prime.
It is a super-2 number, since 2×231001044221312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (23100104422133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 350001582121 + ... + 350001582186.
It is an arithmetic number, because the mean of its divisors is an integer number (4200018985848).
Almost surely, 223100104422131 is an apocalyptic number.
23100104422131 is a deficient number, since it is larger than the sum of its proper divisors (10500047464653).
23100104422131 is a wasteful number, since it uses less digits than its factorization.
23100104422131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 700003164321.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 23100104422131 its reverse (13122440100132), we get a palindrome (36222544522263).
The spelling of 23100104422131 in words is "twenty-three trillion, one hundred billion, one hundred four million, four hundred twenty-two thousand, one hundred thirty-one".
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