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23101441131 = 34324164673
BaseRepresentation
bin10101100000111101…
…000000010001101011
32012121222102210122210
4111200331000101223
5334302432104011
614340200020203
71445322003216
oct254075002153
965558383583
1023101441131
11988518570a
124588761663
1322420b88c2
14119217677d
1590319b6a6
hex560f4046b

23101441131 has 12 divisors (see below), whose sum is σ = 31534911528. Its totient is φ = 15042795264.

The previous prime is 23101441127. The next prime is 23101441141. The reversal of 23101441131 is 13114410132.

It is not a de Polignac number, because 23101441131 - 22 = 23101441127 is a prime.

It is a super-2 number, since 2×231014411312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23101441098 and 23101441107.

It is not an unprimeable number, because it can be changed into a prime (23101441141) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2076790 + ... + 2087883.

It is an arithmetic number, because the mean of its divisors is an integer number (2627909294).

Almost surely, 223101441131 is an apocalyptic number.

23101441131 is a deficient number, since it is larger than the sum of its proper divisors (8433470397).

23101441131 is an equidigital number, since it uses as much as digits as its factorization.

23101441131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4164762 (or 4164719 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 23101441131 its reverse (13114410132), we get a palindrome (36215851263).

It can be divided in two parts, 2310 and 1441131, that added together give a palindrome (1443441).

The spelling of 23101441131 in words is "twenty-three billion, one hundred one million, four hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 3 43 129 1849 5547 4164673 12494019 179080939 537242817 7700480377 23101441131