Base | Representation |
---|---|
bin | 1010100000011010110100… |
… | …10000000101111111000101 |
3 | 10000210201211110122012120212 |
4 | 11100031122100011333011 |
5 | 11012014241133102240 |
6 | 121045521421005205 |
7 | 4603135131231422 |
oct | 520153220057705 |
9 | 100721743565525 |
10 | 23104143253445 |
11 | 73a84595a7511 |
12 | 27118a29b3805 |
13 | cb7932b20c17 |
14 | 59c364578d49 |
15 | 2a0ed2435165 |
hex | 15035a405fc5 |
23104143253445 has 8 divisors (see below), whose sum is σ = 29184180951840. Its totient is φ = 17510508570960.
The previous prime is 23104143253403. The next prime is 23104143253447. The reversal of 23104143253445 is 54435234140132.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 23104143253445 - 242 = 18706096742341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23104143253447) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 121600753871 + ... + 121600754060.
It is an arithmetic number, because the mean of its divisors is an integer number (3648022618980).
Almost surely, 223104143253445 is an apocalyptic number.
It is an amenable number.
23104143253445 is a deficient number, since it is larger than the sum of its proper divisors (6080037698395).
23104143253445 is a wasteful number, since it uses less digits than its factorization.
23104143253445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243201507955.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 23104143253445 its reverse (54435234140132), we get a palindrome (77539377393577).
The spelling of 23104143253445 in words is "twenty-three trillion, one hundred four billion, one hundred forty-three million, two hundred fifty-three thousand, four hundred forty-five".
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