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23105413439 = 172367881987
BaseRepresentation
bin10101100001001100…
…001010000100111111
32012122020220121122022
4111201030022010333
5334304441212224
614340421110355
71445400526253
oct254114120477
965566817568
1023105413439
119887449109
124589b583bb
132242b79994
1411928cc263
159036d365e
hex56130a13f

23105413439 has 16 divisors (see below), whose sum is σ = 25909279488. Its totient is φ = 20490298752.

The previous prime is 23105413411. The next prime is 23105413453. The reversal of 23105413439 is 93431450132.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23105413439 is a prime.

It is a super-3 number, since 3×231054134393 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23105413399 and 23105413408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23105413459) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 414797 + ... + 467190.

It is an arithmetic number, because the mean of its divisors is an integer number (1619329968).

Almost surely, 223105413439 is an apocalyptic number.

23105413439 is a deficient number, since it is larger than the sum of its proper divisors (2803866049).

23105413439 is a wasteful number, since it uses less digits than its factorization.

23105413439 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 882094.

The product of its (nonzero) digits is 38880, while the sum is 35.

The spelling of 23105413439 in words is "twenty-three billion, one hundred five million, four hundred thirteen thousand, four hundred thirty-nine".

Divisors: 1 17 23 67 391 1139 1541 26197 881987 14993779 20285701 59093129 344856917 1004583193 1359141967 23105413439