Base | Representation |
---|---|
bin | 10101100001001100… |
… | …001010000100111111 |
3 | 2012122020220121122022 |
4 | 111201030022010333 |
5 | 334304441212224 |
6 | 14340421110355 |
7 | 1445400526253 |
oct | 254114120477 |
9 | 65566817568 |
10 | 23105413439 |
11 | 9887449109 |
12 | 4589b583bb |
13 | 2242b79994 |
14 | 11928cc263 |
15 | 9036d365e |
hex | 56130a13f |
23105413439 has 16 divisors (see below), whose sum is σ = 25909279488. Its totient is φ = 20490298752.
The previous prime is 23105413411. The next prime is 23105413453. The reversal of 23105413439 is 93431450132.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23105413439 is a prime.
It is a super-3 number, since 3×231054134393 (a number of 32 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23105413399 and 23105413408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23105413459) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 414797 + ... + 467190.
It is an arithmetic number, because the mean of its divisors is an integer number (1619329968).
Almost surely, 223105413439 is an apocalyptic number.
23105413439 is a deficient number, since it is larger than the sum of its proper divisors (2803866049).
23105413439 is a wasteful number, since it uses less digits than its factorization.
23105413439 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 882094.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 23105413439 in words is "twenty-three billion, one hundred five million, four hundred thirteen thousand, four hundred thirty-nine".
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