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23110001311 = 94841243671
BaseRepresentation
bin10101100001011101…
…101010001010011111
32012122120112201000111
4111201131222022133
5334312130020221
614341103310451
71445454525055
oct254135521237
965576481014
1023110001311
119889aa2041
12458b5ab427
132243ac4cb7
1411933641d5
15903cdcbe1
hex56176a29f

23110001311 has 4 divisors (see below), whose sum is σ = 23110339824. Its totient is φ = 23109662800.

The previous prime is 23110001281. The next prime is 23110001323. The reversal of 23110001311 is 11310001132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23110001311 - 25 = 23110001279 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23110001291 and 23110001300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23110001351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26995 + ... + 216676.

It is an arithmetic number, because the mean of its divisors is an integer number (5777584956).

Almost surely, 223110001311 is an apocalyptic number.

23110001311 is a deficient number, since it is larger than the sum of its proper divisors (338513).

23110001311 is an equidigital number, since it uses as much as digits as its factorization.

23110001311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 338512.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 23110001311 its reverse (11310001132), we get a palindrome (34420002443).

The spelling of 23110001311 in words is "twenty-three billion, one hundred ten million, one thousand, three hundred eleven".

Divisors: 1 94841 243671 23110001311