Base | Representation |
---|---|
bin | 1101011100111011010… |
… | …0011111110111111001 |
3 | 211002111222022122220201 |
4 | 3113032310133313321 |
5 | 12241244400311400 |
6 | 254100050122201 |
7 | 22460644144354 |
oct | 3271664376771 |
9 | 732458278821 |
10 | 231103135225 |
11 | 8a012771036 |
12 | 38957b80361 |
13 | 18a400c1cc1 |
14 | b284c4329b |
15 | 6028d5306a |
hex | 35ced1fdf9 |
231103135225 has 6 divisors (see below), whose sum is σ = 286567887710. Its totient is φ = 184882508160.
The previous prime is 231103135187. The next prime is 231103135247. The reversal of 231103135225 is 522531301132.
It can be written as a sum of positive squares in 3 ways, for example, as 54410694121 + 176692441104 = 233261^2 + 420348^2 .
It is not a de Polignac number, because 231103135225 - 215 = 231103102457 is a prime.
It is a super-2 number, since 2×2311031352252 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 231103135193 and 231103135202.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4622062680 + ... + 4622062729.
Almost surely, 2231103135225 is an apocalyptic number.
231103135225 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
231103135225 is a deficient number, since it is larger than the sum of its proper divisors (55464752485).
231103135225 is an equidigital number, since it uses as much as digits as its factorization.
231103135225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9244125419 (or 9244125414 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 231103135225 its reverse (522531301132), we get a palindrome (753634436357).
The spelling of 231103135225 in words is "two hundred thirty-one billion, one hundred three million, one hundred thirty-five thousand, two hundred twenty-five".
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