Base | Representation |
---|---|
bin | 1010100000101000001100… |
… | …01101001010000011000100 |
3 | 10000211102100211211211111112 |
4 | 11100110012031022003010 |
5 | 11012123442210211400 |
6 | 121053110102424152 |
7 | 4603511063212310 |
oct | 520240615120304 |
9 | 100742324754445 |
10 | 23111323132100 |
11 | 7400503440625 |
12 | 2713167432058 |
13 | cb8508487728 |
14 | 59c845d5ab40 |
15 | 2a12a2931835 |
hex | 15050634a0c4 |
23111323132100 has 216 divisors, whose sum is σ = 59181175412352. Its totient is φ = 7669592179200.
The previous prime is 23111323132091. The next prime is 23111323132147. The reversal of 23111323132100 is 123132311132.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 462877337 + ... + 462927263.
Almost surely, 223111323132100 is an apocalyptic number.
23111323132100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 23111323132100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29590587706176).
23111323132100 is an abundant number, since it is smaller than the sum of its proper divisors (36069852280252).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
23111323132100 is a wasteful number, since it uses less digits than its factorization.
23111323132100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50243 (or 50109 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 23111323132100 its reverse (123132311132), we get a palindrome (23234455443232).
The spelling of 23111323132100 in words is "twenty-three trillion, one hundred eleven billion, three hundred twenty-three million, one hundred thirty-two thousand, one hundred".
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