Base | Representation |
---|---|
bin | 10101100001100010… |
… | …110001010110001101 |
3 | 2012122200001210100101 |
4 | 111201202301112031 |
5 | 334313000411303 |
6 | 14341152131101 |
7 | 1445502106144 |
oct | 254142612615 |
9 | 65580053311 |
10 | 23111341453 |
11 | 988a8279a2 |
12 | 458bb36a91 |
13 | 2244173c95 |
14 | 11935d275b |
15 | 903ea4d1d |
hex | 5618b158d |
23111341453 has 4 divisors (see below), whose sum is σ = 23163511968. Its totient is φ = 23059170940.
The previous prime is 23111341439. The next prime is 23111341469. The reversal of 23111341453 is 35414311132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23111341453 - 213 = 23111333261 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23111344453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26084593 + ... + 26085478.
It is an arithmetic number, because the mean of its divisors is an integer number (5790877992).
Almost surely, 223111341453 is an apocalyptic number.
It is an amenable number.
23111341453 is a deficient number, since it is larger than the sum of its proper divisors (52170515).
23111341453 is an equidigital number, since it uses as much as digits as its factorization.
23111341453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52170514.
The product of its digits is 4320, while the sum is 28.
Adding to 23111341453 its reverse (35414311132), we get a palindrome (58525652585).
The spelling of 23111341453 in words is "twenty-three billion, one hundred eleven million, three hundred forty-one thousand, four hundred fifty-three".
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