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23112402433 = 431489360979
BaseRepresentation
bin10101100001100110…
…110100011000000001
32012122202001200201221
4111201212310120001
5334313233334213
614341230555041
71445514115321
oct254146643001
965582050657
1023112402433
11989039203a
124590368a81
132244455b93
1411937cb281
1590411438d
hex5619b4601

23112402433 has 8 divisors (see below), whose sum is σ = 23665848800. Its totient is φ = 22559681088.

The previous prime is 23112402431. The next prime is 23112402461. The reversal of 23112402433 is 33420421132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23112402433 - 21 = 23112402431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23112402398 and 23112402407.

It is not an unprimeable number, because it can be changed into a prime (23112402431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116463 + ... + 244516.

It is an arithmetic number, because the mean of its divisors is an integer number (2958231100).

Almost surely, 223112402433 is an apocalyptic number.

It is an amenable number.

23112402433 is a deficient number, since it is larger than the sum of its proper divisors (553446367).

23112402433 is a wasteful number, since it uses less digits than its factorization.

23112402433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 362511.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 23112402433 its reverse (33420421132), we get a palindrome (56532823565).

The spelling of 23112402433 in words is "twenty-three billion, one hundred twelve million, four hundred two thousand, four hundred thirty-three".

Divisors: 1 43 1489 64027 360979 15522097 537497731 23112402433