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2311300201320 = 2333511349557461
BaseRepresentation
bin100001101000100100001…
…110100011101101101000
322011221212111002120202000
4201220210032203231220
5300332020322420240
64525444024411000
7325662113361645
oct41504416435550
98157774076660
102311300201320
11811242787640
12313b41916a60
13139c54558c26
147dc206c8dcc
15401c7779430
hex21a243a3b68

2311300201320 has 256 divisors, whose sum is σ = 8428825440000. Its totient is φ = 558708710400.

The previous prime is 2311300201313. The next prime is 2311300201321. The reversal of 2311300201320 is 231020031132.

2311300201320 is a `hidden beast` number, since 2 + 311 + 30 + 0 + 2 + 0 + 1 + 320 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 2311300201293 and 2311300201302.

It is not an unprimeable number, because it can be changed into a prime (2311300201321) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3867390 + ... + 4424850.

It is an arithmetic number, because the mean of its divisors is an integer number (32925099375).

Almost surely, 22311300201320 is an apocalyptic number.

2311300201320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2311300201320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4214412720000).

2311300201320 is an abundant number, since it is smaller than the sum of its proper divisors (6117525238680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2311300201320 is a wasteful number, since it uses less digits than its factorization.

2311300201320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 557841 (or 557831 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 2311300201320 its reverse (231020031132), we get a palindrome (2542320232452).

The spelling of 2311300201320 in words is "two trillion, three hundred eleven billion, three hundred million, two hundred one thousand, three hundred twenty".