Base | Representation |
---|---|
bin | 1101011101000001111… |
… | …0110101001111101111 |
3 | 211002120220202211221221 |
4 | 3113100132311033233 |
5 | 12241324014310111 |
6 | 254102523404211 |
7 | 22461433112125 |
oct | 3272036651757 |
9 | 732526684857 |
10 | 231131010031 |
11 | 8a02747a869 |
12 | 38965383667 |
13 | 18a45b0187c |
14 | b28881b915 |
15 | 602b50c371 |
hex | 35d07b53ef |
231131010031 has 4 divisors (see below), whose sum is σ = 231481740600. Its totient is φ = 230780279464.
The previous prime is 231131010029. The next prime is 231131010037. The reversal of 231131010031 is 130010131132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 231131010031 - 21 = 231131010029 is a prime.
It is a super-2 number, since 2×2311310100312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 231131009987 and 231131010014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (231131010037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175364296 + ... + 175365613.
It is an arithmetic number, because the mean of its divisors is an integer number (57870435150).
Almost surely, 2231131010031 is an apocalyptic number.
231131010031 is a deficient number, since it is larger than the sum of its proper divisors (350730569).
231131010031 is an equidigital number, since it uses as much as digits as its factorization.
231131010031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350730568.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 231131010031 its reverse (130010131132), we get a palindrome (361141141163).
The spelling of 231131010031 in words is "two hundred thirty-one billion, one hundred thirty-one million, ten thousand, thirty-one".
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