231133134041433 has 160 divisors (see below), whose sum is σ = 376765201612800. Its totient is φ = 140359399703424.

The previous prime is 231133134041401. The next prime is 231133134041441. The reversal of 231133134041433 is 334140431331132.

231133134041433 is a `hidden beast` number, since 2 + 3 + 1 + 133 + 13 + 40 + 41 + 433 = 666.

It is not a de Polignac number, because 231133134041433 - 2⁵ = 231133134041401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (231133134041333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 49397974588 + ... + 49397979266.

It is an arithmetic number, because the mean of its divisors is an integer number (2354782510080).

Almost surely, 2^{231133134041433} is an apocalyptic number.

It is an amenable number.

231133134041433 is a deficient number, since it is larger than the sum of its proper divisors (145632067571367).

231133134041433 is a wasteful number, since it uses less digits than its factorization.

231133134041433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6313 (or 6304 counting only the distinct ones).

The product of its (nonzero) digits is 93312, while the sum is 36.

Adding to 231133134041433 its reverse (334140431331132), we get a palindrome (565273565372565).

The spelling of 231133134041433 in words is "two hundred thirty-one trillion, one hundred thirty-three billion, one hundred thirty-four million, forty-one thousand, four hundred thirty-three".