23114055041131 has 4 divisors (see below), whose sum is σ = 23392537632072. Its totient is φ = 22835572450192.

The previous prime is 23114055041117. The next prime is 23114055041171. The reversal of 23114055041131 is 13114055041132.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23114055041131 - 2⁷ = 23114055041003 is a prime.

It is a super-2 number, since 2×23114055041131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23114055041093 and 23114055041102.

It is not an unprimeable number, because it can be changed into a prime (23114055041171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139241295346 + ... + 139241295511.

It is an arithmetic number, because the mean of its divisors is an integer number (5848134408018).

Almost surely, 2^{23114055041131} is an apocalyptic number.

23114055041131 is a deficient number, since it is larger than the sum of its proper divisors (278482590941).

23114055041131 is an equidigital number, since it uses as much as digits as its factorization.

23114055041131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278482590940.

The product of its (nonzero) digits is 7200, while the sum is 31.

Subtracting from 23114055041131 its reverse (13114055041132), we obtain a palindrome (9999999999999).

The spelling of 23114055041131 in words is "twenty-three trillion, one hundred fourteen billion, fifty-five million, forty-one thousand, one hundred thirty-one".