23114112042433 has 4 divisors (see below), whose sum is σ = 23123960409520. Its totient is φ = 23104263675348.

The previous prime is 23114112042331. The next prime is 23114112042467. The reversal of 23114112042433 is 33424021141132.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23114112042433 - 2⁴¹ = 20915088786881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23114112042395 and 23114112042404.

It is not an unprimeable number, because it can be changed into a prime (23114112042533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4924180023 + ... + 4924184716.

It is an arithmetic number, because the mean of its divisors is an integer number (5780990102380).

Almost surely, 2^{23114112042433} is an apocalyptic number.

It is an amenable number.

23114112042433 is a deficient number, since it is larger than the sum of its proper divisors (9848367087).

23114112042433 is an equidigital number, since it uses as much as digits as its factorization.

23114112042433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9848367086.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 23114112042433 its reverse (33424021141132), we get a palindrome (56538133183565).

The spelling of 23114112042433 in words is "twenty-three trillion, one hundred fourteen billion, one hundred twelve million, forty-two thousand, four hundred thirty-three".