23114245012503 has 4 divisors (see below), whose sum is σ = 30818993350008. Its totient is φ = 15409496675000.

The previous prime is 23114245012489. The next prime is 23114245012549. The reversal of 23114245012503 is 30521054241132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23114245012503 - 2⁵ = 23114245012471 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23114245012583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3852374168748 + ... + 3852374168753.

It is an arithmetic number, because the mean of its divisors is an integer number (7704748337502).

Almost surely, 2^{23114245012503} is an apocalyptic number.

23114245012503 is a deficient number, since it is larger than the sum of its proper divisors (7704748337505).

23114245012503 is an equidigital number, since it uses as much as digits as its factorization.

23114245012503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7704748337504.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 23114245012503 its reverse (30521054241132), we get a palindrome (53635299253635).

The spelling of 23114245012503 in words is "twenty-three trillion, one hundred fourteen billion, two hundred forty-five million, twelve thousand, five hundred three".