Base | Representation |
---|---|
bin | 100001101000101011101… |
… | …011100100000001110111 |
3 | 22011222012012101110211122 |
4 | 201220223223210001313 |
5 | 300332244330322203 |
6 | 4525504252454155 |
7 | 325665162261446 |
oct | 41505353440167 |
9 | 8158165343748 |
10 | 2311425245303 |
11 | 8112a7323a79 |
12 | 313b7777a35b |
13 | 139c7442a955 |
14 | 7dc33158d5d |
15 | 401d3729538 |
hex | 21a2bae4077 |
2311425245303 has 4 divisors (see below), whose sum is σ = 2328296962560. Its totient is φ = 2294553528048.
The previous prime is 2311425245231. The next prime is 2311425245309. The reversal of 2311425245303 is 3035425241132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2311425245303 - 210 = 2311425244279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2311425245309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8435858423 + ... + 8435858696.
It is an arithmetic number, because the mean of its divisors is an integer number (582074240640).
Almost surely, 22311425245303 is an apocalyptic number.
2311425245303 is a deficient number, since it is larger than the sum of its proper divisors (16871717257).
2311425245303 is a wasteful number, since it uses less digits than its factorization.
2311425245303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16871717256.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 2311425245303 in words is "two trillion, three hundred eleven billion, four hundred twenty-five million, two hundred forty-five thousand, three hundred three".
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