2311431231 has 8 divisors (see below), whose sum is σ = 3263197104. Its totient is φ = 1450309760.

The previous prime is 2311431223. The next prime is 2311431277. The reversal of 2311431231 is 1321341132.

2311431231 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2311431231 - 2³ = 2311431223 is a prime.

It is a super-2 number, since 2×2311431231² = 10685428671284350722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2311431198 and 2311431207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2311431281) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22661040 + ... + 22661141.

It is an arithmetic number, because the mean of its divisors is an integer number (407899638).

Almost surely, 2^2311431231 is an apocalyptic number.

2311431231 is a deficient number, since it is larger than the sum of its proper divisors (951765873).

2311431231 is a wasteful number, since it uses less digits than its factorization.

2311431231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45322201.

The product of its digits is 432, while the sum is 21.

The square root of 2311431231 is about 48077.3463389984. The cubic root of 2311431231 is about 1322.1893631379.

Adding to 2311431231 its reverse (1321341132), we get a palindrome (3632772363).

Subtracting from 2311431231 its reverse (1321341132), we obtain a palindrome (990090099).

It can be divided in two parts, 23114 and 31231, that added together give a palindrome (54345).

The spelling of 2311431231 in words is "two billion, three hundred eleven million, four hundred thirty-one thousand, two hundred thirty-one".