Base | Representation |
---|---|
bin | 1010100000101101110101… |
… | …10001010010000110100011 |
3 | 10000211201011222010201121102 |
4 | 11100112322301102012203 |
5 | 11012201143220014110 |
6 | 121054330440345015 |
7 | 4603646126345126 |
oct | 520267261220643 |
9 | 100751158121542 |
10 | 23114352501155 |
11 | 7401818440413 |
12 | 2713871a7516b |
13 | cb889bc829b6 |
14 | 59ca5240a3bd |
15 | 2a13cd8775a5 |
hex | 1505bac521a3 |
23114352501155 has 4 divisors (see below), whose sum is σ = 27737223001392. Its totient is φ = 18491482000920.
The previous prime is 23114352501151. The next prime is 23114352501169. The reversal of 23114352501155 is 55110525341132.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 23114352501155 - 22 = 23114352501151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23114352501151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2311435250111 + ... + 2311435250120.
It is an arithmetic number, because the mean of its divisors is an integer number (6934305750348).
Almost surely, 223114352501155 is an apocalyptic number.
23114352501155 is a deficient number, since it is larger than the sum of its proper divisors (4622870500237).
23114352501155 is an equidigital number, since it uses as much as digits as its factorization.
23114352501155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4622870500236.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 23114352501155 its reverse (55110525341132), we get a palindrome (78224877842287).
The spelling of 23114352501155 in words is "twenty-three trillion, one hundred fourteen billion, three hundred fifty-two million, five hundred one thousand, one hundred fifty-five".
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