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23115134535 = 354393510271
BaseRepresentation
bin10101100001110001…
…001111011001000111
32012122221012111110220
4111201301033121013
5334314433301120
614341405315423
71445546254533
oct254161173107
965587174426
1023115134535
119891988779
124591265b73
132244ba15cc
141193cdcbc3
159044a3b40
hex561c4f647

23115134535 has 16 divisors (see below), whose sum is σ = 37068472320. Its totient is φ = 12299986080.

The previous prime is 23115134533. The next prime is 23115134561. The reversal of 23115134535 is 53543151132.

It is not a de Polignac number, because 23115134535 - 21 = 23115134533 is a prime.

It is a super-2 number, since 2×231151345352 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23115134496 and 23115134505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23115134533) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1748551 + ... + 1761720.

It is an arithmetic number, because the mean of its divisors is an integer number (2316779520).

Almost surely, 223115134535 is an apocalyptic number.

23115134535 is a deficient number, since it is larger than the sum of its proper divisors (13953337785).

23115134535 is a wasteful number, since it uses less digits than its factorization.

23115134535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3510718.

The product of its digits is 27000, while the sum is 33.

Adding to 23115134535 its reverse (53543151132), we get a palindrome (76658285667).

The spelling of 23115134535 in words is "twenty-three billion, one hundred fifteen million, one hundred thirty-four thousand, five hundred thirty-five".

Divisors: 1 3 5 15 439 1317 2195 6585 3510271 10530813 17551355 52654065 1541008969 4623026907 7705044845 23115134535