Base | Representation |
---|---|
bin | 1010100000101111011111… |
… | …10110110101111011001011 |
3 | 10000211210111001001102120121 |
4 | 11100113233312311323023 |
5 | 11012210004221313201 |
6 | 121054555054204111 |
7 | 4604010162632062 |
oct | 520275766657313 |
9 | 100753431042517 |
10 | 23115243151051 |
11 | 7402135166907 |
12 | 2713a801b3637 |
13 | cb89b165457c |
14 | 59cad88111d9 |
15 | 2a1431b589a1 |
hex | 1505efdb5ecb |
23115243151051 has 8 divisors (see below), whose sum is σ = 23121336546000. Its totient is φ = 23109150247680.
The previous prime is 23115243151037. The next prime is 23115243151081. The reversal of 23115243151051 is 15015134251132.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23115243151051 - 211 = 23115243149003 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23115243150998 and 23115243151016.
It is not an unprimeable number, because it can be changed into a prime (23115243151081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 105743896 + ... + 105962266.
It is an arithmetic number, because the mean of its divisors is an integer number (2890167068250).
Almost surely, 223115243151051 is an apocalyptic number.
23115243151051 is a deficient number, since it is larger than the sum of its proper divisors (6093394949).
23115243151051 is a wasteful number, since it uses less digits than its factorization.
23115243151051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245789.
The product of its (nonzero) digits is 18000, while the sum is 34.
The spelling of 23115243151051 in words is "twenty-three trillion, one hundred fifteen billion, two hundred forty-three million, one hundred fifty-one thousand, fifty-one".
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