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2312013101341 = 13274447391789
BaseRepresentation
bin100001101001001110101…
…110000011100100011101
322012000201011112122201111
4201221032232003210131
5300340000323220331
64530042452342021
7326015561051446
oct41511656034435
98160634478644
102312013101341
11811579137a09
12314100614911
1313a039163b68
147dc8b2602cd
154021a148db1
hex21a4eb8391d

2312013101341 has 8 divisors (see below), whose sum is σ = 2314281589760. Its totient is φ = 2309745408048.

The previous prime is 2312013101323. The next prime is 2312013101353. The reversal of 2312013101341 is 1431013102132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2312013101341 - 213 = 2312013093149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2312013101141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5705275 + ... + 6097063.

It is an arithmetic number, because the mean of its divisors is an integer number (289285198720).

Almost surely, 22312013101341 is an apocalyptic number.

It is an amenable number.

2312013101341 is a deficient number, since it is larger than the sum of its proper divisors (2268488419).

2312013101341 is a wasteful number, since it uses less digits than its factorization.

2312013101341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 397563.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 2312013101341 its reverse (1431013102132), we get a palindrome (3743026203473).

The spelling of 2312013101341 in words is "two trillion, three hundred twelve billion, thirteen million, one hundred one thousand, three hundred forty-one".

Divisors: 1 1327 4447 391789 5901169 519904003 1742285683 2312013101341