231211383112133 has 4 divisors (see below), whose sum is σ = 231541213901868. Its totient is φ = 230881552322400.

The previous prime is 231211383112121. The next prime is 231211383112141. The reversal of 231211383112133 is 331211383112132.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 195751942535044 + 35459440577089 = 13991138^2 + 5954783^2 .

It is a cyclic number.

It is not a de Polignac number, because 231211383112133 - 2¹⁰ = 231211383111109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231211383112093 and 231211383112102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231211383412133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164915393816 + ... + 164915395217.

It is an arithmetic number, because the mean of its divisors is an integer number (57885303475467).

Almost surely, 2^{231211383112133} is an apocalyptic number.

It is an amenable number.

231211383112133 is a deficient number, since it is larger than the sum of its proper divisors (329830789735).

231211383112133 is an equidigital number, since it uses as much as digits as its factorization.

231211383112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329830789734.

The product of its digits is 15552, while the sum is 35.

Subtracting 231211383112133 from its reverse (331211383112132), we obtain a palindrome (99999999999999).

The spelling of 231211383112133 in words is "two hundred thirty-one trillion, two hundred eleven billion, three hundred eighty-three million, one hundred twelve thousand, one hundred thirty-three".