231211404112133 has 8 divisors (see below), whose sum is σ = 231283484315520. Its totient is φ = 231139325986560.

The previous prime is 231211404112127. The next prime is 231211404112153. The reversal of 231211404112133 is 331211404112132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 231211404112133 - 2²² = 231211399917829 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231211404112096 and 231211404112105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231211404112123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 239259941 + ... + 240224357.

It is an arithmetic number, because the mean of its divisors is an integer number (28910435539440).

Almost surely, 2^{231211404112133} is an apocalyptic number.

It is an amenable number.

231211404112133 is a deficient number, since it is larger than the sum of its proper divisors (72080203387).

231211404112133 is an equidigital number, since it uses as much as digits as its factorization.

231211404112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1038907.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 231211404112133 its reverse (331211404112132), we get a palindrome (562422808224265).

Subtracting 231211404112133 from its reverse (331211404112132), we obtain a palindrome (99999999999999).

The spelling of 231211404112133 in words is "two hundred thirty-one trillion, two hundred eleven billion, four hundred four million, one hundred twelve thousand, one hundred thirty-three".