2312131204013 has 4 divisors (see below), whose sum is σ = 2312139782268. Its totient is φ = 2312122625760.

The previous prime is 2312131203997. The next prime is 2312131204037. The reversal of 2312131204013 is 3104021312132.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 318279890569 + 1993851313444 = 564163^2 + 1412038^2 .

It is a cyclic number.

It is not a de Polignac number, because 2312131204013 - 2⁴ = 2312131203997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2312131204013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2312131204073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3871256 + ... + 4428417.

It is an arithmetic number, because the mean of its divisors is an integer number (578034945567).

Almost surely, 2^{2312131204013} is an apocalyptic number.

It is an amenable number.

2312131204013 is a deficient number, since it is larger than the sum of its proper divisors (8578255).

2312131204013 is an equidigital number, since it uses as much as digits as its factorization.

2312131204013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8578254.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 2312131204013 its reverse (3104021312132), we get a palindrome (5416152516145).

The spelling of 2312131204013 in words is "two trillion, three hundred twelve billion, one hundred thirty-one million, two hundred four thousand, thirteen".