Base | Representation |
---|---|
bin | 1010100000111010111110… |
… | …01010000100110100010111 |
3 | 10000212101101111110200120122 |
4 | 11100131133022010310113 |
5 | 11012310114242243223 |
6 | 121101454345222155 |
7 | 4604315660304032 |
oct | 520353712046427 |
9 | 100771344420518 |
10 | 23121405431063 |
11 | 7404807657005 |
12 | 27150bba9195b |
13 | cb945422b7c4 |
14 | 59d120dc4019 |
15 | 2a1692b495c8 |
hex | 15075f284d17 |
23121405431063 has 4 divisors (see below), whose sum is σ = 23122575977088. Its totient is φ = 23120234885040.
The previous prime is 23121405431017. The next prime is 23121405431077. The reversal of 23121405431063 is 36013450412132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23121405431063 - 230 = 23120331689239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23121405430063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 585243383 + ... + 585282888.
It is an arithmetic number, because the mean of its divisors is an integer number (5780643994272).
Almost surely, 223121405431063 is an apocalyptic number.
23121405431063 is a deficient number, since it is larger than the sum of its proper divisors (1170546025).
23121405431063 is a wasteful number, since it uses less digits than its factorization.
23121405431063 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1170546024.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 23121405431063 its reverse (36013450412132), we get a palindrome (59134855843195).
The spelling of 23121405431063 in words is "twenty-three trillion, one hundred twenty-one billion, four hundred five million, four hundred thirty-one thousand, sixty-three".
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