Base | Representation |
---|---|
bin | 1010100000111100010011… |
… | …11011011001100001101111 |
3 | 10000212110020111201011121122 |
4 | 11100132021323121201233 |
5 | 11012313101442112030 |
6 | 121102053501251155 |
7 | 4604342522465330 |
oct | 520361173314157 |
9 | 100773214634548 |
10 | 23122123004015 |
11 | 7405045709202 |
12 | 2715280263abb |
13 | cb9539ab1699 |
14 | 59d18c414287 |
15 | 2a16d5b3d8e5 |
hex | 150789ed986f |
23122123004015 has 16 divisors (see below), whose sum is σ = 31734381381120. Its totient is φ = 15843149429280.
The previous prime is 23122123004009. The next prime is 23122123004027. The reversal of 23122123004015 is 51040032122132.
It is not a de Polignac number, because 23122123004015 - 224 = 23122106226799 is a prime.
It is a super-3 number, since 3×231221230040153 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 250382981 + ... + 250475310.
It is an arithmetic number, because the mean of its divisors is an integer number (1983398836320).
Almost surely, 223122123004015 is an apocalyptic number.
23122123004015 is a deficient number, since it is larger than the sum of its proper divisors (8612258377105).
23122123004015 is a wasteful number, since it uses less digits than its factorization.
23122123004015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 500859622.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 23122123004015 its reverse (51040032122132), we get a palindrome (74162155126147).
The spelling of 23122123004015 in words is "twenty-three trillion, one hundred twenty-two billion, one hundred twenty-three million, four thousand, fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.089 sec. • engine limits •