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2312404034443 = 19121705475497
BaseRepresentation
bin100001101001100110000…
…001010110001110001011
322012001201102011010010021
4201221212001112032023
5300341300413100233
64530145335401311
7326031345661216
oct41514601261613
98161642133107
102312404034443
1181175987a818
123141ab523237
1313a09c14c519
147dcc714477d
154023e61ae2d
hex21a6605638b

2312404034443 has 4 divisors (see below), whose sum is σ = 2434109509960. Its totient is φ = 2190698558928.

The previous prime is 2312404034419. The next prime is 2312404034459. The reversal of 2312404034443 is 3444304042132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2312404034443 - 237 = 2174965080971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2312404034399 and 2312404034408.

It is not an unprimeable number, because it can be changed into a prime (2312404034243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60852737730 + ... + 60852737767.

It is an arithmetic number, because the mean of its divisors is an integer number (608527377490).

Almost surely, 22312404034443 is an apocalyptic number.

2312404034443 is a deficient number, since it is larger than the sum of its proper divisors (121705475517).

2312404034443 is a wasteful number, since it uses less digits than its factorization.

2312404034443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121705475516.

The product of its (nonzero) digits is 110592, while the sum is 34.

Adding to 2312404034443 its reverse (3444304042132), we get a palindrome (5756708076575).

The spelling of 2312404034443 in words is "two trillion, three hundred twelve billion, four hundred four million, thirty-four thousand, four hundred forty-three".

Divisors: 1 19 121705475497 2312404034443