Base | Representation |
---|---|
bin | 1010100001000001110001… |
… | …01001100111001110011111 |
3 | 10000212201210210120012022000 |
4 | 11100200320221213032133 |
5 | 11012340102403314320 |
6 | 121103300414253343 |
7 | 4604505255530223 |
oct | 520407051471637 |
9 | 100781723505260 |
10 | 23125054354335 |
11 | 740630a35007a |
12 | 2715959ab7253 |
13 | cb98b61aabbb |
14 | 59d38986a783 |
15 | 2a1808171c90 |
hex | 150838a6739f |
23125054354335 has 16 divisors (see below), whose sum is σ = 41111207741280. Its totient is φ = 12333362322240.
The previous prime is 23125054354291. The next prime is 23125054354399. The reversal of 23125054354335 is 53345345052132.
23125054354335 is a `hidden beast` number, since 2 + 3 + 1 + 2 + 50 + 54 + 3 + 543 + 3 + 5 = 666.
It is not a de Polignac number, because 23125054354335 - 214 = 23125054337951 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85648349326 + ... + 85648349595.
It is an arithmetic number, because the mean of its divisors is an integer number (2569450483830).
Almost surely, 223125054354335 is an apocalyptic number.
23125054354335 is a deficient number, since it is larger than the sum of its proper divisors (17986153386945).
23125054354335 is a wasteful number, since it uses less digits than its factorization.
23125054354335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171296698935 (or 171296698929 counting only the distinct ones).
The product of its (nonzero) digits is 3240000, while the sum is 45.
The spelling of 23125054354335 in words is "twenty-three trillion, one hundred twenty-five billion, fifty-four million, three hundred fifty-four thousand, three hundred thirty-five".
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