2313124213133 has 4 divisors (see below), whose sum is σ = 2313642506688. Its totient is φ = 2312605919580.

The previous prime is 2313124213123. The next prime is 2313124213139. The reversal of 2313124213133 is 3313124213132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2313124213133 - 2⁴ = 2313124213117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2313124213096 and 2313124213105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2313124213139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 259140083 + ... + 259149008.

It is an arithmetic number, because the mean of its divisors is an integer number (578410626672).

Almost surely, 2^{2313124213133} is an apocalyptic number.

It is an amenable number.

2313124213133 is a deficient number, since it is larger than the sum of its proper divisors (518293555).

2313124213133 is an equidigital number, since it uses as much as digits as its factorization.

2313124213133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 518293554.

The product of its digits is 7776, while the sum is 29.

Adding to 2313124213133 its reverse (3313124213132), we get a palindrome (5626248426265).

Subtracting 2313124213133 from its reverse (3313124213132), we obtain a palindrome (999999999999).

The spelling of 2313124213133 in words is "two trillion, three hundred thirteen billion, one hundred twenty-four million, two hundred thirteen thousand, one hundred thirty-three".