23140555433 has 4 divisors (see below), whose sum is σ = 23150053380. Its totient is φ = 23131057488.

The previous prime is 23140555379. The next prime is 23140555439. The reversal of 23140555433 is 33455504132.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9229060624 + 13911494809 = 96068^2 + 117947^2 .

It is a cyclic number.

It is not a de Polignac number, because 23140555433 - 2¹² = 23140551337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 23140555393 and 23140555402.

It is not an unprimeable number, because it can be changed into a prime (23140555439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4745318 + ... + 4750191.

It is an arithmetic number, because the mean of its divisors is an integer number (5787513345).

Almost surely, 2^23140555433 is an apocalyptic number.

It is an amenable number.

23140555433 is a deficient number, since it is larger than the sum of its proper divisors (9497947).

23140555433 is an equidigital number, since it uses as much as digits as its factorization.

23140555433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9497946.

The product of its (nonzero) digits is 108000, while the sum is 35.

The spelling of 23140555433 in words is "twenty-three billion, one hundred forty million, five hundred fifty-five thousand, four hundred thirty-three".