Base | Representation |
---|---|
bin | 110100100111110000000101… |
… | …100001010101101010000001 |
3 | 1010100102111120022100120121221 |
4 | 310213300011201111222001 |
5 | 220313222331230400301 |
6 | 2140113305221515041 |
7 | 66514162610614123 |
oct | 6447600541255201 |
9 | 1110374508316557 |
10 | 231430110403201 |
11 | 67816a5aa52236 |
12 | 21b58857872a81 |
13 | 9c199c5513b08 |
14 | 41213c4563213 |
15 | 1bb506565dda1 |
hex | d27c05855a81 |
231430110403201 has 4 divisors (see below), whose sum is σ = 231430213830400. Its totient is φ = 231430006976004.
The previous prime is 231430110403171. The next prime is 231430110403237. The reversal of 231430110403201 is 102304011034132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 231430110403201 - 27 = 231430110403073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (231430110403001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48281241 + ... + 52857718.
It is an arithmetic number, because the mean of its divisors is an integer number (57857553457600).
Almost surely, 2231430110403201 is an apocalyptic number.
It is an amenable number.
231430110403201 is a deficient number, since it is larger than the sum of its proper divisors (103427199).
231430110403201 is a wasteful number, since it uses less digits than its factorization.
231430110403201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103427198.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 231430110403201 its reverse (102304011034132), we get a palindrome (333734121437333).
The spelling of 231430110403201 in words is "two hundred thirty-one trillion, four hundred thirty billion, one hundred ten million, four hundred three thousand, two hundred one".
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