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23143314101 = 431367393721
BaseRepresentation
bin10101100011011100…
…101111001010110101
32012201220020011120112
4111203130233022311
5334344142022401
614344253312405
71446340631645
oct254334571265
965656204515
1023143314101
1198a6885476
12459a795705
13224a989acb
141197956525
15906bbd3bb
hex56372f2b5

23143314101 has 8 divisors (see below), whose sum is σ = 23698914624. Its totient is φ = 22588503840.

The previous prime is 23143314079. The next prime is 23143314107. The reversal of 23143314101 is 10141334132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23143314101 - 26 = 23143314037 is a prime.

It is a super-2 number, since 2×231433141012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23143314107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 138080 + ... + 255641.

It is an arithmetic number, because the mean of its divisors is an integer number (2962364328).

Almost surely, 223143314101 is an apocalyptic number.

It is an amenable number.

23143314101 is a deficient number, since it is larger than the sum of its proper divisors (555600523).

23143314101 is a wasteful number, since it uses less digits than its factorization.

23143314101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 395131.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 23143314101 its reverse (10141334132), we get a palindrome (33284648233).

The spelling of 23143314101 in words is "twenty-three billion, one hundred forty-three million, three hundred fourteen thousand, one hundred one".

Divisors: 1 43 1367 58781 393721 16930003 538216607 23143314101