23143314122 has 4 divisors (see below), whose sum is σ = 34714971186. Its totient is φ = 11571657060.

The previous prime is 23143314121. The next prime is 23143314163. The reversal of 23143314122 is 22141334132.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 14173140601 + 8970173521 = 119051^2 + 94711^2 .

It is a super-2 number, since 2×23143314122² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23143314091 and 23143314100.

It is not an unprimeable number, because it can be changed into a prime (23143314121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5785828529 + ... + 5785828532.

Almost surely, 2^23143314122 is an apocalyptic number.

23143314122 is a deficient number, since it is larger than the sum of its proper divisors (11571657064).

23143314122 is a wasteful number, since it uses less digits than its factorization.

23143314122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11571657063.

The product of its digits is 3456, while the sum is 26.

Adding to 23143314122 its reverse (22141334132), we get a palindrome (45284648254).

The spelling of 23143314122 in words is "twenty-three billion, one hundred forty-three million, three hundred fourteen thousand, one hundred twenty-two".