Base | Representation |
---|---|
bin | 10101100011011100… |
… | …110100001010010001 |
3 | 2012201220021012121201 |
4 | 111203130310022101 |
5 | 334344143201140 |
6 | 14344253551201 |
7 | 1446341045362 |
oct | 254334641221 |
9 | 65656235551 |
10 | 23143334545 |
11 | 98a6899871 |
12 | 459a7a5501 |
13 | 224a9961c6 |
14 | 119795db69 |
15 | 906bc449a |
hex | 563734291 |
23143334545 has 4 divisors (see below), whose sum is σ = 27772001460. Its totient is φ = 18514667632.
The previous prime is 23143334537. The next prime is 23143334633. The reversal of 23143334545 is 54543334132.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3909250576 + 19234083969 = 62524^2 + 138687^2 .
It is a cyclic number.
It is not a de Polignac number, because 23143334545 - 23 = 23143334537 is a prime.
It is a super-2 number, since 2×231433345452 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2314333450 + ... + 2314333459.
It is an arithmetic number, because the mean of its divisors is an integer number (6943000365).
Almost surely, 223143334545 is an apocalyptic number.
It is an amenable number.
23143334545 is a deficient number, since it is larger than the sum of its proper divisors (4628666915).
23143334545 is an equidigital number, since it uses as much as digits as its factorization.
23143334545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4628666914.
The product of its digits is 259200, while the sum is 37.
Adding to 23143334545 its reverse (54543334132), we get a palindrome (77686668677).
The spelling of 23143334545 in words is "twenty-three billion, one hundred forty-three million, three hundred thirty-four thousand, five hundred forty-five".
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