Base | Representation |
---|---|
bin | 100001101100000001100… |
… | …001111101111111000011 |
3 | 22012022110020111001200011 |
4 | 201230001201331333003 |
5 | 300412121320220103 |
6 | 4531300300005351 |
7 | 326153116200340 |
oct | 41540141757703 |
9 | 8168406431604 |
10 | 2315013054403 |
11 | 812878576065 |
12 | 3147b9230857 |
13 | 13a3c682cc0a |
14 | 800938537c7 |
15 | 403436cdd6d |
hex | 21b0187dfc3 |
2315013054403 has 24 divisors (see below), whose sum is σ = 2802833779200. Its totient is φ = 1867883947488.
The previous prime is 2315013054283. The next prime is 2315013054407. The reversal of 2315013054403 is 3044503105132.
2315013054403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2315013054403 - 213 = 2315013046211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2315013054407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2925238 + ... + 3631396.
It is an arithmetic number, because the mean of its divisors is an integer number (116784740800).
Almost surely, 22315013054403 is an apocalyptic number.
2315013054403 is a deficient number, since it is larger than the sum of its proper divisors (487820724797).
2315013054403 is an equidigital number, since it uses as much as digits as its factorization.
2315013054403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 706499 (or 706342 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 2315013054403 its reverse (3044503105132), we get a palindrome (5359516159535).
The spelling of 2315013054403 in words is "two trillion, three hundred fifteen billion, thirteen million, fifty-four thousand, four hundred three".
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