Base | Representation |
---|---|
bin | 110100101000111101110001… |
… | …110111000011010001111111 |
3 | 1010100201110220010120202122121 |
4 | 310220331301313003101333 |
5 | 220321104203244204210 |
6 | 2140215503141023411 |
7 | 66523205104162624 |
oct | 6450756167032177 |
9 | 1110643803522577 |
10 | 231513532413055 |
11 | 67849379557a32 |
12 | 21b70a596b4b67 |
13 | 9c2482b5a9919 |
14 | 412545999834b |
15 | 1bb72e92816da |
hex | d28f71dc347f |
231513532413055 has 8 divisors (see below), whose sum is σ = 280513483934112. Its totient is φ = 183412662571488.
The previous prime is 231513532413017. The next prime is 231513532413073. The reversal of 231513532413055 is 550314235315132.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 231513532413055 - 27 = 231513532412927 is a prime.
It is a super-2 number, since 2×2315135324130552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 224770419304 + ... + 224770420333.
It is an arithmetic number, because the mean of its divisors is an integer number (35064185491764).
Almost surely, 2231513532413055 is an apocalyptic number.
231513532413055 is a deficient number, since it is larger than the sum of its proper divisors (48999951521057).
231513532413055 is a wasteful number, since it uses less digits than its factorization.
231513532413055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 449540839745.
The product of its (nonzero) digits is 810000, while the sum is 43.
Adding to 231513532413055 its reverse (550314235315132), we get a palindrome (781827767728187).
The spelling of 231513532413055 in words is "two hundred thirty-one trillion, five hundred thirteen billion, five hundred thirty-two million, four hundred thirteen thousand, fifty-five".
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