23154330321445 has 4 divisors (see below), whose sum is σ = 27785196385740. Its totient is φ = 18523464257152.

The previous prime is 23154330321443. The next prime is 23154330321461. The reversal of 23154330321445 is 54412303345132.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14472957183556 + 8681373137889 = 3804334^2 + 2946417^2 .

It is a cyclic number.

It is not a de Polignac number, because 23154330321445 - 2¹ = 23154330321443 is a prime.

It is a super-2 number, since 2×23154330321445² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23154330321398 and 23154330321407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23154330321443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2315433032140 + ... + 2315433032149.

It is an arithmetic number, because the mean of its divisors is an integer number (6946299096435).

Almost surely, 2^{23154330321445} is an apocalyptic number.

It is an amenable number.

23154330321445 is a deficient number, since it is larger than the sum of its proper divisors (4630866064295).

23154330321445 is an equidigital number, since it uses as much as digits as its factorization.

23154330321445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4630866064294.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 23154330321445 its reverse (54412303345132), we get a palindrome (77566633666577).

The spelling of 23154330321445 in words is "twenty-three trillion, one hundred fifty-four billion, three hundred thirty million, three hundred twenty-one thousand, four hundred forty-five".