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23200310112103 = 118119644631763
BaseRepresentation
bin1010100011001101111100…
…01111100010111101100111
310001010221001111112210102201
411101212332033202331213
511020103213342041403
6121202024134315331
74613111212106635
oct521467617427547
9101127044483381
1023200310112103
117435218255803
122728460ab8b47
13cc3a1a461497
145a2c884bc355
152a375eda921d
hex1519be3e2f67

23200310112103 has 4 divisors (see below), whose sum is σ = 23219954745048. Its totient is φ = 23180665479160.

The previous prime is 23200310112053. The next prime is 23200310112113. The reversal of 23200310112103 is 30121101300232.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23200310112103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (23200310112113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9822314701 + ... + 9822317062.

It is an arithmetic number, because the mean of its divisors is an integer number (5804988686262).

Almost surely, 223200310112103 is an apocalyptic number.

23200310112103 is a deficient number, since it is larger than the sum of its proper divisors (19644632945).

23200310112103 is a wasteful number, since it uses less digits than its factorization.

23200310112103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19644632944.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 23200310112103 its reverse (30121101300232), we get a palindrome (53321411412335).

The spelling of 23200310112103 in words is "twenty-three trillion, two hundred billion, three hundred ten million, one hundred twelve thousand, one hundred three".

Divisors: 1 1181 19644631763 23200310112103