Base | Representation |
---|---|
bin | 1010100011010000100111… |
… | …01100011101100110000111 |
3 | 10001011001202102012102200001 |
4 | 11101220103230131212013 |
5 | 11020114132400140110 |
6 | 121202422310302131 |
7 | 4613161560634513 |
oct | 521502354354607 |
9 | 101131672172601 |
10 | 23201743755655 |
11 | 7435893533393 |
12 | 27287a1057947 |
13 | cc3bb848c48a |
14 | 5a2d82a6b143 |
15 | 2a37e5b9763a |
hex | 151a13b1d987 |
23201743755655 has 8 divisors (see below), whose sum is σ = 29479862654352. Its totient is φ = 17469548239488.
The previous prime is 23201743755647. The next prime is 23201743755661. The reversal of 23201743755655 is 55655734710232.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23201743755655 - 23 = 23201743755647 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23201743755596 and 23201743755605.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 136480845537 + ... + 136480845706.
It is an arithmetic number, because the mean of its divisors is an integer number (3684982831794).
Almost surely, 223201743755655 is an apocalyptic number.
23201743755655 is a deficient number, since it is larger than the sum of its proper divisors (6278118898697).
23201743755655 is a wasteful number, since it uses less digits than its factorization.
23201743755655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 272961691265.
The product of its (nonzero) digits is 26460000, while the sum is 55.
The spelling of 23201743755655 in words is "twenty-three trillion, two hundred one billion, seven hundred forty-three million, seven hundred fifty-five thousand, six hundred fifty-five".
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