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232054113442 = 2116027056721
BaseRepresentation
bin1101100000011110000…
…0001100010010100010
3211011222020202100210011
43120013200030102202
512300221323112232
6254334300555134
722523342263534
oct3300740142242
9734866670704
10232054113442
118a460552048
1238b82552aaa
1318b621270c8
14b33526d854
15608259e547
hex360780c4a2

232054113442 has 4 divisors (see below), whose sum is σ = 348081170166. Its totient is φ = 116027056720.

The previous prime is 232054113413. The next prime is 232054113469. The reversal of 232054113442 is 244311450232.

232054113442 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 163692258921 + 68361854521 = 404589^2 + 261461^2 .

It is a super-2 number, since 2×2320541134422 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58013528359 + ... + 58013528362.

Almost surely, 2232054113442 is an apocalyptic number.

232054113442 is a deficient number, since it is larger than the sum of its proper divisors (116027056724).

232054113442 is a wasteful number, since it uses less digits than its factorization.

232054113442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116027056723.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 232054113442 its reverse (244311450232), we get a palindrome (476365563674).

The spelling of 232054113442 in words is "two hundred thirty-two billion, fifty-four million, one hundred thirteen thousand, four hundred forty-two".

Divisors: 1 2 116027056721 232054113442